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Change and Accumulation

When the Rate Depends on the Amount

Last timeDoing It With Arithmetic, and the Error You Buy

A quantity whose rate is proportional to how much of it there is multiplies by a fixed factor in every fixed stretch of time, and the rule describing it is its own rate.

Most rates in the sciences are not given as functions of the clock. They are given in

terms of the quantity itself. Interest depends on the balance, decays per second depend

on the number of atoms left, heat lost depends on how much hotter the object still is

than the room. In every case the thing that is changing is also what sets the speed of

the change.

That self-reference sounds like it should make the problem harder. It makes it easier,

because it can be solved completely, and the answer is the most frequently met rule in

applied mathematics.

FIG 1The equation, and its answer
the proportionality constant: the fractional change per unit time. Positive gives growth, negative gives decay, and its units are one over time
the amount at the start. The rate equation cannot determine it, which is the arbitrary constant from the lesson on the two questions, here carrying real information
the limit of compounding a proportional increase over ever shorter intervals, about two point seven one eight. It is not chosen, it is what that limit equals
the factor by which the starting amount has been multiplied by time t. It is a multiplier rather than an addition, which is the whole character of this situation
The left side is a statement about rates with the unknown quantity on both sides, which is why it cannot be solved by totalling something up directly. The right side is the answer. Two things are worth checking rather than accepting: that this rule really does have the claimed rate, and where the number e comes from. The second is the subject of the next figure, and the first follows from it, because the defining property of that number is exactly that the rule built from it is its own rate.

Where the number comes from

Take a quantity growing at one hundred per cent per unit time and apply the growth in

instalments. One instalment at the end gives a doubling. Four instalments of a quarter

each, with each instalment computed on the amount then present, give more, because the

later instalments are computed on an already grown amount.

FIG 2The same growth rate, applied in more and more instalments
stepinstalments in the periodfraction added each timefactor after the whole periodhow far short of the limitwhat happened
11120.7183All at the end: the amount doubles and nothing compounds.
240.252.44140.2769Quarterly. Each quarter earns on what the earlier quarters added.
3120.08332.6130.1052Monthly, and most of the gain over yearly has already been had.
4520.01922.69260.0257Weekly. The remaining gain is under one per cent of the factor.
53650.00272.71460.0037Daily, and the last column shows how little is left to gain.
5 steps
The third column is rising and the fourth is falling towards nothing, so the factor is approaching a ceiling rather than growing without bound as the instalments multiply. That ceiling is about two point seven one eight and it is the number e. The first three rows are the identical arithmetic to the march in the previous lesson, which is not a coincidence at all: marching this quantity forward with a step is exactly compounding in instalments of that size, so the error of the march and the shortfall in this table are the same quantity seen twice.

The rule built from that number has the property that its rate is itself. Everything

else follows: multiply the input by a constant and the chain rule from the earlier

lesson says the rate picks up that constant, which gives exactly the proportionality

wanted, and multiplying by a starting amount scales both sides equally.

The lesson stops here

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The rest of this course

  1. 01A Rule, and the Picture of It
  2. 02How Fast, Exactly Hereopening only
  3. 03One Rule Inside Anotheropening only
  4. 04Adding Up Thin Slicesopening only
  5. 05The Two Questions Are One Questionopening only
  6. 06The Straight Line That Fits, Then the Parabolaopening only
  7. 07Doing It With Arithmetic, and the Error You Buyopening only
  8. 08When the Rate Depends on the Amountyou are here

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